Question

1)what are possible remainders in a=10q+r

2)write 18 as product of prime factors

3)in a=br+r,if a=15; q=2 and r=1.then find the value of b

plz say me the answers fast ​

Answer 1

Answer:

1) infinite

2) 3 x 2 x 3

3) a=br+r

br=a=r

b=(a-r)/r

now substitute the values

a = 15 and r=1

now,

b= (15-1)/1

= 14/1

= 14

hence b = 14

Step-by-step explanation: