Math, asked by amansharma000003, 9 months ago

1. What could be the possible ‘one's'digits of the square root of each of the following
numbers?
(i) 9801
(ii) 99856
(iii) 998001 (iv) 657666025​

Answers

Answered by shreyas6728
3

Answer:

1. 1

2. 7

3. 1

4. 5

Step-by-step explanation:

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Answered by simikennady
15

Answer:

i) 1 and 9

ii) 4 and 6

iii) 1 and 9

iv) 5

Step-by-step explanation:

i) Only the squares of numbers with one's' digit as 1 or 9 can end with one (as 1*1 = 1; 9*9=81)

ii) Only the squares of numbers with one's' digit as 4 or 6 can end with six (as 4*4 = 16; 6 * 6=36)

iii) Only the squares of numbers with one's' digit as 1 or 9 can end with one (as 1*1 = 1; 9*9=81)

iv) Only the squares of numbers with one's' digit as 5 can end with five

(as 5 * 5 = 25)

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