Math, asked by hfhviyfd, 5 hours ago

1. What could be the possible 'one's digits of the square root of each of the following numbers? (i) 9801 (ii) 99856 (iii) 998001 (iv) 657666025

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Answers

Answered by Satinderpal2244
1

Step-by-step explanation:

part 1 : 9801

unit digit or one's place digit = 1

now we have to see that 1 comes in unit digit of square of which numbers

1 square= 1(unit digit =1)

9 square=81 (unit digit =1)

So, the possible ones digit of square root of 9801 are= 1 and 9

part 2: 99856

unit digit or one's place digit = 6

now we have to see that 6 comes in unit digit of square of which numbers

4 square= 16(unit digit =6)

6 square= 36(unit digit =6)

So, the possible ones digit of square root of 99856 are= 4 and 6

part 3: 998001

unit digit or one's place digit = 1

now we have to see that 1 comes in unit digit of square of which numbers

1 square= 1(unit digit =1)

9 square=81 (unit digit =1)

So, the possible ones digit of square root of 998001 are= 1 and 9

part 4: 657666025

unit digit or one's place digit = 5

now we have to see that 5 comes in unit digit of square of which numbers

5 square= 25 (unit digit =5)

As 5 comes only in unit digit of square of 5

So, the possible ones digit of square root of 657666025 is= 5

This is the answer.Hope you understood

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Answered by nileshdebnath2009
0

Answer:

please mark as branlist answer

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