Math, asked by keshavbinjola4, 1 year ago

1. What could be the possible 'one's' digits of the square root of each of the following
numbers?
(1) 9801 (ii) 99856
(iii) 998001 (iv) 657666025

Answers

Answered by Anonymous
22

Answer:

Step-by-step explanation:

(i)  1 or 9

( 1*1=1 and 9*9=81 ends at 1)

(ii)  4 or 6

(4*4=16 and 6*6=36 ends at 6)

(ii) 1 or 9

(same as (i) )

(iv) 5

( 5*5=25 ends at 5)


keshavbinjola4: please can you explain how we get these answers
Anonymous: I have edited in answer as per your request
Answered by wachimsiddique33
0

Answer:

Solution:

i. We know that the unit’s digit of the square of a number having digit as unit’s

place 1 is 1 and also 9 is 1[92=81 whose unit place is 1].

∴ Unit’s digit of the square root of number 9801 is equal to 1 or 9.

ii. We know that the unit’s digit of the square of a number having digit as unit’s

place 6 is 6 and also 4 is 6 [62=36 and 42=16, both the squares have unit digit 6].

∴ Unit’s digit of the square root of number 99856 is equal to 6.

iii. We know that the unit’s digit of the square of a number having digit as unit’s

place 1 is 1 and also 9 is 1[92=81 whose unit place is 1].

∴ Unit’s digit of the square root of number 998001 is equal to 1 or 9.

iv. We know that the unit’s digit of the square of a number having digit as unit’s

place 5 is 5.

∴ Unit’s digit of the square root of number 657666025 is equal to 5.

Step-by-step explanation:

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