Question

(1) What happens if an iron nail is kept in solution of copper sulphate ?
( 2 ) Complete the following equations and balance them :
(i) Ca(s) + H2O(1) ►
(ii) Al(s) + HCl(aq) →
( 3 ) What would you take as anode, cathode and electrolyte in the electrolytic refining
of a metal M?​

Answer 1

Answer:

Iron nails lose their shiny appearance because an insoluble layer of copper is formed on the nails, Meanwhile, the solution,CuSO

4

loses its blue color because of the formation of FeSO

4

. This reaction is called displacement reaction in which the reactive element Iron, Fe has displaced less reactive Copper from its solution, The chemical equation can be written as:

Fe+CuSO

4

→Cu+FeSO

4

Answer 2

Answer:

1. When an iron nail immersed in the solution of copper sulphate than iron displaces copper from the solution of copper sulphate because iron is more reactive than copper
2. Ca(s)+H2O(l)=Ca(OH)2
3. Al(s)+HCl(aq) → AlCl3(aq)+H2(g)
4. During electrolytic refining, impure metal is made anode and a thin strip of pure metal M is made cathode and the electrolyte used is the soluble salt of Metal M which is to be refined

Explanation:

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