Question

1) What happens when:
a) Dry chlorine gas is passed through lime water.
b) Bleaching Powder reacts with dilute Sulphuric acid.



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Answer 1

Answer: hey mate here is your answer

Explanation:

a)   when cholrine  gas is passed  through lime water  it, it is rapidly absorbed  forms bleaching powder or chloride of lime . the reaction is

$Ca(OH )_{2} + Cl$=

$CAOCl_{2} + H_{2} 0$

b) when bleaching powder  with dilute sulphuric acid  all  chlorine present in it is liberated  .this chlorine acts as bleaching agent

$CaoCl_{2} + H_{2}SO_{4}$ =$CaSO_{4} +Cl_{2} +H_{2} o$

hope this may help you

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