Question

1) What happens when an aqueous solution of NaSo4 reacts with an aqueous solution of Bacl2? State the physical condition of reactants in which the reaction between them will not take place.

2)identify the oxidation , reduction ,oxidizing agent and reducing agent in the following equation

I. SO2 +2H2S = 2H2O +3S

II. H2S +Cl2 =S +2HCL

III. MnO2 +4HCL = MnCL2 +2H2O +Cl2

IV. CuO +H2 = Cu =H2O

V. PbS +4H2O = PbSO4 +4H2O

Answer 1

Here are the answers :-

Answer 1:-

When Na2SO4 reacts with BaCl2 a white precipitate of BaSO4 is formed.
In the above case, Double Displacement or precipitation reaction occurs.

The reaction involved is:-

Na2SO4 (aq) + BaCl2 (aq) -------->
BaSO4 (s) + 2NaCl (aq)

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Answer 2:-

I. Oxidised substance- H2S
Reduced substance- SO2
Oxidising agent- SO2
Reducing agent- H2S

II. Oxidised substance -H2S
Reduced substance- Cl2
Oxidising agent- Cl2
Reducing agent- H2S

III. Oxidised substance- H2
Reduced substance- CuO
Oxidising agent- CuO
Reducing agent- H2

IV. Oxidised substance- PbS
Reduced substance- H2O
Oxidising agent- H2O
Reducing agent - Pbs




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