Question

1. What is mass of Cu metal produced at the cathode during the the

passage of 5 ampere current through CuSO4soltion for 100

minutes. Molar mass of Cu is 63.5 g mol -1​

Answer 1

Answer:

i hope this will be helpful ..

Answer 2

Answer:

9.87g of copper metal is produced at the cathode.

Explanation:

Given:

Current (I)= 5A

Time (t)= 100 min

100 × 60= 6000sec

Molar mass of Copper= 63.5 g/mol

We have to calculate the mass of copper produced at the cathode according to Faraday's first law of electrolysis.

According to this law,

The mass of substance deposited at an electrode is directly proportional to the amount of electric current passed through the electrolyte.

We have W=ZIT

W- Amount the substance deposited

Z- Electrochemical equivalent

I- Current passed

T- Time taken

Also,

Z= $\frac{M}{nF}$

M- Molecular mass

n- moles of electrons

F- Faraday's constant

Step by step working:

W= $\frac{63.5}{2*96500}$×5×6000

W= $\frac{63.5}{193000}$×30000

W= 9.87 g

Result:

9.87g of copper will be deposited at cathode.