1
What is the age of father, if the sum of the ages of a father and his son in years is 65 and
twice the difference of their ages in years is 50?
Answers
Answered by
3
Step-by-step explanation:
Correct answer is: (b) 45 years Let age of Father = x Years Let age of son = y years x +y = 65 2(x-y)=50 Solving the above equations Father’s Age =x = 45 yearsRead more on Sarthaks.com - https://www.sarthaks.com/1213858/what-the-father-the-ages-father-and-his-son-years-and-twice-the-difference-their-ages-years?show=1213869#a1213869
Answered by
0
ANSWER 45 YEARS
X+Y =65
2(X-Y) =50
2X-2Y=50
Y=65-X
X-Y=50/2=25
X-(65-X)=25
X-65+X=25
2X=25+65
X=90/2
X=45
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