Math, asked by chiragsurana9047, 7 hours ago

1
What is the age of father, if the sum of the ages of a father and his son in years is 65 and
twice the difference of their ages in years is 50?​

Answers

Answered by joelbathan69
3

Step-by-step explanation:

Correct answer is: (b) 45 years Let age of Father = x Years Let age of son = y years x +y = 65 2(x-y)=50 Solving the above equations Father’s Age =x = 45 yearsRead more on Sarthaks.com - https://www.sarthaks.com/1213858/what-the-father-the-ages-father-and-his-son-years-and-twice-the-difference-their-ages-years?show=1213869#a1213869

Answered by sisterbuddies20
0

ANSWER 45 YEARS

X+Y =65

2(X-Y) =50

2X-2Y=50

Y=65-X

X-Y=50/2=25

X-(65-X)=25

X-65+X=25

2X=25+65

X=90/2

X=45

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