Question

1. what is the area of the triangle BCD? 2.Draw another triangle of the same area? 3.how many such triangles can be drawn? 4.what are the general properties of these triangles?​

Answer 1

$\large\fbox \purple{ Question \: 1.}$

Area of triangle BCD=

$\frac{1}{2} \times base \times height$

OR

$s\sqrt{(s - a)(s - b)(s - c) } \\ \\ here. \: s = \frac{perimeter}{2} \\ \\ a. \: b. \: c. \: = are \: the \: sides \: of \: triangle$

$\large\fbox \pink{ Question \: 2 }$

refer, to the attachment!!!

$\large\fbox \green{ Question \: 3 }$

If two sides remain the same length, you can’t alter the angle between the two sides without altering the area. I can think of only one way in which there can be two triangles of the same area, and that is if one of the triangles has 180 degrees between two sides, and the third side is equal to the sum of the other two sides… And a triangle where there is 0 degrees between two sides, and the third side equals the difference in length between the other two. Both of these triangles, unfortunately also qualify as straight lines, with an area of 0.

$\large\fbox \red{ Question \: 4 }$

A triangle has three sides, three angles, and three vertices. The sum of all internal angles of a triangle is always equal to 180°. This is called the angle sum property of a triangle. The sum of the length of any two sides of a triangle is greater than the length of the third side.