Question

1.What is the diagonal of a square with side 5 cm?
2.The side of a rhombus is 4 cm what is its area​

Answer 1

Answer:

1.Length of diagonal=side*√2

5√2

length of the diagonal is 5√2cm

2. The maximum area of the rhombus whose area 4cm is 16sq cm

hoping it helps you...

Answer 2

Answer:

1. 7.07 cm (to 3 s.f.) , 2. 16$cm^{2}$

Step-by-step explanation:

1. By using pythagoras theorem, (which is $a^{2}$+$b^{2}$ = $c^{2}$ )

$\sqrt{5^{2}+5^{2} }$ = 7.07 cm (to 3 s.f.)

2.  Fact 1: The rhombus has 4 equal sides

    Fact 2: The rhombus's area is the same as the square's area, as long as the sides are the same length.

Hence by using these 2 facts,

The area of a rhombus = $4^{2}$

                                      = 16 $cm^{2}$