Question

1.
What is the difference between the sum of 16-3(a+b+5ab-5ab2+6), 23ab2-12a²b and the sum of
13a²b-3ab?, 14+ab?​

Answer 1

Answer:

$38ab^{2}$ - $25a^{2} b$ - 3a - 3b - 13ab - 16

Step-by-step explanation:

16 - 3(a + b + 5ab - $5ab^{2}$ + 6)

= 16 - 3a - 3b - 15ab  $+15ab^{2}$  - 18

= $+15ab^{2}$ - 3a - 3b - 15ab - 2

Adding, $23ab^{2}$ - $12a^{2} b$ to the above:

= $38ab^{2}$  - $12a^{2} b$ - 3a - 3b - 15ab - 2

In order to get desired difference, we are to subtract the last two elements from the above:

($38ab^{2}$  - $12a^{2} b$ - 3a - 3b - 15ab - 2) - ($13a^{2} b$ - 3ab) - (14 + ab)

= $38ab^{2}$ - $12a^{2} b$ - $13a^{2} b$ - 3a - 3b - 15ab + 3ab - ab - 2 - 14

= $38ab^{2}$ - $25a^{2} b$ - 3a - 3b - 13ab - 16