Question

1. What is the hardness of a solution containing 0.585 g of NaCl and 0.6 g MgSO, per litre? (Ans: 500
ppm.)
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Answer 1

Answer:

don't know this question is very hard sorry

Answer 2

Answer:

500 ppm

Explanation:

    Here the Nacl does not take part in producing Hardness and the MgSO4 alone take part in producing Hardness.

GIVEN:

 0.6 g/L of C  =  0.6 * 10^3 mg/L  =  600 mg/L

FORMULA:

 Hardness = mg/L of hardness producing salt ×(100/molar mass of the salt)

SOLUTION:

 Molar mass of the salt(MgSO4) = 120

Hardness = 600 × (100/120)

                 = 6000/12

                 = 500 ppm