Question

1. What is the HM of 1, 12, 1/3, .... 1/n?​

Answer 1

Answer:

Step-by-step explanation:

Given numbers are 1,1/2,1/3....,1/n

Reciprocals of them are 1,2,3,4...,n

Mean=(1+2+3+....+n)/n=n(n+1)/2n

n+1/2

So required Hm=2/n+1

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