Question

1. What is the largest number that den
1206 and 321 learling Jemaindey 6?​

Answer 1

Answer:

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Answer 2

ANSWER

1206–6 = 1200

1206–6 = 1200321–6 - 315

1206–6 = 1200321–6 - 315Factors of

1206–6 = 1200321–6 - 315Factors of1200 = 2x2x2x2x3x5x5

1206–6 = 1200321–6 - 315Factors of1200 = 2x2x2x2x3x5x5315 = 3x5x7

1206–6 = 1200321–6 - 315Factors of1200 = 2x2x2x2x3x5x5315 = 3x5x7HCF = 3x5 = 15

1206–6 = 1200321–6 - 315Factors of1200 = 2x2x2x2x3x5x5315 = 3x5x7HCF = 3x5 = 151206/15 = 80 and 6/15

1206–6 = 1200321–6 - 315Factors of1200 = 2x2x2x2x3x5x5315 = 3x5x7HCF = 3x5 = 151206/15 = 80 and 6/15321/15 = 21 and 6/15

1206–6 = 1200321–6 - 315Factors of1200 = 2x2x2x2x3x5x5315 = 3x5x7HCF = 3x5 = 151206/15 = 80 and 6/15321/15 = 21 and 6/15So the number is 15. Answer.

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