Question

1) what is the minimum value of 'n' for which 'f' orbits exist?

2) what is the minimum value of 'n' for which 'h' orbits exist?

please guys help me it's very urgent for me and please don't write unnecessary answers ​

Answer 1

Answer:

1.For f-orbitals, l = 3. As for any value 'n' of principal quantum number, the Azimuthal quantum number (l) can have a value from zero to (n – 1).

2.The lowest value of n that allows g orbitals to exist is 5

Explanation:

PLS MARK AS BRAINLIST

Answer 2

$\huge{\underline{\boxed{\boxed{\mathfrak{Answer \ :}}}}}$

★ For f-orbital, Azimuthal quantum number, l = 3 as :

• l=0 ⇒s
• l=1 ⇒p,
• l=2 ⇒d,
• l=3 ⇒f,
• l=4 ⇒g,

As value of l is from 0 to (n-1) where n = Principal quantum number

$\therefore$ 3 = n - 1

⇒ n = 3 + 1 = 4

$\boxed{\boxed{\mathfrak{n \ = \ 4}}}$