Question

(1) What is the oxidation number (ON) of sulphur in H2SO4 and in H2S2O7?​

Answer 1

Answer:

the oxidation number of both the sulphur atoms in H2S2O7 is +6.

Answer 2

Answer:

The oxidation number of sulphur in H2SO7 is +6

The oxidation number of H and O are +1 and −2 respectively

2(+1)+2x+7(−2)=0

∴2+2x−14=0

∴2x=+12

∴x=+6

The oxidation number of sulphur in H2SO4 is also +6

Charge on hydrogen is +1 and charge on oxygen atom is -2. Total charge on HH2SO is 0.

Let the oxidation state of sulphur be x

∴2(+1)+x+4(−2)=0

∴x−6=0

∴x=+6

Explanation:

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