Question

1. What is the percent by mass concentration of a solution that contains 5.30 g of salt dissolved in 19.7 g of water?

Given:

Find:

Formula:

Solution:

2. What is the percent by volume of a solution formed by mixing 25mL of isopropanol with 45mL water?

Given:

Find:

Formula:

Solution:

3.How many grams of glucose are needed to prepare 400mL of 5% glucose solution?

Given:

Find:

Formula:

Solution:​

Answer 1

Explanation:

take bro mark me brainlest

Answer 2

1. Percent by mass concentration is 21.2%

2. Percent by volume of solution is 35.7%

3. Amount of glucose required is 20gm

Explanation:

1.

Given : mass of solute = 5.30g

mass of solvent = 19.7g

Find : percent by mass concentration =

Formula :

$\frac{mass \: of \: solute}{mass \: of \: solute \: + mass \: of \: solvent} \times 100$

Solution :

$= \frac{5.30}{5.30 + 19.7} \times 100$

$= \frac{5.30}{25} \times 100$

$= 21.2\%$

2.

Given : Volume of isopropanol = 25ml

Volume of water = 45ml

Find : percent by volume of solution =

Formula :

$\frac{volume \: of \: solute}{volume \: of \: solute + volume \: of \: solvent} \times 100$

Solution :

$= \frac{25}{25 + 45} \times 100$

$= \frac{25}{70} \times 100$

$= 33.3\%$

3.

Given : Compound glucose is used to prepare 400ml of 5% glucose solution

Find : how much gram of glucose required

Explanation :

Let grams of glucose required be m.

5% glucose solution means that there should be 5grams of glucose per 100ml of solution.

Here, volume of wate given is 400ml.

For preparing this solution is 100ml, 5grams of glucose would have been sufficient.

But, since the volume given is 400ml which is 4times the volume the mass required will also be 4 times of 5grams.

Mass of glucose required = 5*4

= 20grams

Solution : 20grams of glucose required.