1.what is the percent by mass of a solution prepared by dissolving 8.0 g of table sugar in 45 g of water? 2.what is the concentration of solution made by dissolving 75 grams of naCl in 325 grams of water? 3.your teacher mixed 55 mililiters of isoproply alcohol with enough water to make 350 mililiter of solution.what is the percentage by volume of the solution? 4.what is the percentage of a solution that is made by mixing 250 mililiters of soduim silicate in 850 mililiters of sulotion?
Answers
Answer:
To find the percent by mass of a solution, you need to divide the mass of the solute (in this case, table sugar) by the mass of the solvent (in this case, water). Multiplying the result by 100 gives you the percent by mass of the solute in the solution. In this case, the percent by mass of the solution would be:
(8.0 g table sugar / 45 g water) * 100 = 17.78% table sugar
To find the concentration of a solution, you can use the following formula:
Concentration (in moles/liter) = (number of moles of solute) / (volume of solvent in liters)
To find the number of moles of solute, you need to divide the mass of the solute (in this case, sodium chloride) by its molar mass. The molar mass of sodium chloride is 58.44 g/mol. So, the concentration of the solution in moles/liter would be:
(75 g NaCl / 58.44 g/mol) / (325 g H2O / 1000 g/L) = 0.4227 moles/liter
To find the percentage by volume of a solution, you need to divide the volume of the solute (in this case, isopropyl alcohol) by the total volume of the solution, and then multiply the result by 100. In this case, the percentage by volume of the solution would be:
(55 mL isopropyl alcohol / 350 mL solution) * 100 = 15.71% isopropyl alcohol
To find the percentage of a solution, you need to divide the volume of the solute (in this case, sodium silicate) by the total volume of the solution, and then multiply the result by 100. In this case, the percentage of the solution would be:
(250 mL sodium silicate / 1100 mL solution) * 100 = 22.73% sodium silicate