Question

1. What is the pH of a 2.35×10-2 M solution of the strong acid HCl?
HCl(aq) + H2O(ℓ) → Cl-(aq) + H3O+(aq)
[HCl]0 = 2.35×10-2



2. A 0.234-M aqueous solution of a weak acid has a pH of 3.85. Calculate Ka for the acid.
Ka = 

3. What is the pH of a 8.68×10-2 M aqueous solution of sodium acetate, NaCH3COO at 25 °C? (Ka for CH3COOH = 1.8×10-5)

pH = 

Answer 1

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