1 What is the resistance of the inductive coil
takes 5A current across 240V, 50Hz supply
at 0.8 power factor?
A 48
B 4250
C 38.40
D 26.60
Answers
Answer:
42.50
Explanation:
Inductive Resistance of the coil is (B) 42.5 Ω
Given:
Current in the circuit
Potential difference
Frequency
Power factor
To find:
Inductive reactance
Solution:
- We know, in a circuit, if only resistance is present, then the voltage and current in the circuit are always in the same phase.
∅
Where, is the peak voltage and
∅ is the power factor
- And, in an inductive circuit, the respective voltage and current will be in a phase difference of
.
- Hence, in an LR circuit, the phase difference between the resistance and inductance will be
.
(
∅)
∅
Step 2
We have,
Hence,
We know, ∅
;
Substituting this value in the equation, we get
∅
Step 3
Now, We know,
We have the value of voltage
, hence,
The peak value of voltage
Substituting the known values in , we get
∅
Hence, the potential difference through Inductor will be .
Step 4
Now,
According to Ohm's law, we have
Substituting the given values in the equation, we get
Ω
Final answer:
Hence, the resistance of the Inductive coil is .