1.what is the value of tan40°tan50°tan60°?
2.Find the xintercept of this equation :2x+3y=12
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- tan 40°×tan 50°×60
- tan 40°× cot(90-50) × tan 60
- tan 40°×cot 40°× tan 60°
- tan 40°×1/tan40°× tan 60°
- tan 60°= root 3
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Answer:
1. tan40.tan50.tan60 = (1/cot40) x tan50 x tan60
= [1/tan (90-40)] x tan50 x tan60
= (1/tan50) x tan50 x tan60
= 1 x tan60
= tan60
= √3
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