Question

1. What is the work to be done to increase the velocity of a car from 36km/hr to 72 km/hr
mass of the car is 1600kg?​

Answer 1

Answer:

Work Done = The Change in Kinetic Energy

= 1/2mv2 - 1/2 mu2

The Mass of car = 1500 kg

Intial Velocity = 36 km/h

= 36 * 5 / 18

= 2 * 5

= 10 m/s

Final Velocity = 72 km/hr

= 72 * 5/18

= 5 * 4

= 20 m/s

Work Done = 1/2 mv2 - 1/2 mu2

= 1/2 m(v2 - u2)

= 1/2 * 1500 ( 20 * 20 - 10 * 10)

= 750 ( 400 - 100)

= 750 * 300

= 225000 J

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Answer 2

Answer:

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Explanation:

Work Done = The Change in Kinetic Energy

= 1/2mv2 - 1/2 mu2

The Mass of car = 1500 kg

Intial Velocity = 36 km/h

= 36 * 5 / 18

= 2 * 5

= 10 m/s

Final Velocity = 72 km/hr

= 72 * 5/18

= 5 * 4

= 20 m/s

Work Done = 1/2 mv2 - 1/2 mu2

= 1/2 m(v2 - u2)

= 1/2 * 1500 ( 20 * 20 - 10 * 10)

= 750 ( 400 - 100)

= 750 * 300

= 225000 J

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