Question

1. What mass of oxygen is consumed by the
complete combustion of 21.0 grams of ethylene?
A) 24.1g
C) 60.59
B) 720g
D) 69.09​

Answer 1

Answer:

c 60.59 is ans

Explanation:

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Answer 2

Answer:

72 grams of oxygen is consumed by the complete combustion of 21.0 grams of ethylene

Explanation:

The reaction proceeds as follows:-

$\mathrm{C_2H_4+3O_2\rightarrow 2CO_2+2H_2O}$                (1)

Where,

C₂H₄=Ethylene

O₂=Oxygen

CO₂=carbon dioxide

H₂O=water

The molar mass of ethylene=28 grams

The molar mass of oxygen =32 grams

From equation (1) we interpret that 28 grams of ethylene consume 3× 32 grams of oxygen. So, 1 gram of ethylene will react with $\frac{3\times 32}{28}$ grams of oxygen. So, 21 grams of ethylene will react with $\frac{3\times 32\times 21}{28}=72$  grams of oxygen.

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