Question

1. What must be subtracted from 5x2 + 3xy + 3y2 + 7 to get 4x2 - 2xy - 7y2 + 3
(a)x4 - 5xy + 10y4
(b)x2 + 5xy + 10y2 + 4
(c)x2 + 5xy - 10y2 - 4
d)x2 + 5xy + 10y2 - 4​

Answer 1

Answer:

B

Step-by-step explanation:

(5x^2+3xy+3y^2+7) - (A) = 4x^2-2xy-7y^2+3

(5x^2+3xy+3y^2+7)-(4x^2-2xy-7y^2+3) = A

(5x^2+3xy+3y^2+7-4x^2+2xy+7y^2-3 =A

x^2+5xy+10y^2+4 = A

Answer 2

Answer:

option b . x^2 + 5xy + 10y^2 + 4 ✓

____________

Given :

1st number = 5x^2 + 3xy + 3y^2 + 7

difference of two number = 4x^2 - 2xy - 7y^2 + 3

To find 2nd number :

Let the 2nd number be x .

Solution :

( 5x^2 + 3xy + 3y^2 + 7 ) - x = 4x^2 - 2xy - 7y^2 + 3

- x = ( 4x^2 - 2xy - 7y^2 + 3 ) - ( 5x^2 + 3xy + 3y^2 + 7 )

- x = 4x^2 - 2xy - 7y^2 + 3 - 5x^2 - 3xy - 3y^2 - 7

- x = -x^2 - 5xy - 10y^2 - 4

x = x^2 + 5xy + 10y^2 + 4

Hence , x^2 + 5xy + 10y^2 + 4 must be subtracted from 5x^2 + 3xy + 3y^2 + 7 to get 4x^2 - 2xy - 7y^2 + 3 .