Question

1. What should be added to-3/32 to get 53/96?
2. What should be added to-3/20 to get 2whole 9/20?​

Answer 1

(1.) Let x be added to -3/32 to get 53/96;

$</strong><strong>→</strong><strong> \frac{ - 3}{32} +x = \frac{53}{96} \\ \\ </strong><strong>→</strong><strong> x = \frac{53}{96} - \frac{ - 3}{32} \\ \\ </strong><strong>→</strong><strong> x = \frac{53}{96} + \frac{3}{32} \\ \\ </strong><strong>→</strong><strong> x = \frac{53 + 9}{96} \\ \\ </strong><strong>→</strong><strong> x = \frac{62}{96} = \frac{31}{48}$

(2.) Let x be added to-3/20 to get 2 whole 9/20

$</strong><strong>→</strong><strong> \frac{ - 3}{20} + x = \frac{49}{20} \\ \\ </strong><strong>→</strong><strong> x = \frac{49}{20} - \frac{ - 3}{20} \\ \\ </strong><strong>→</strong><strong> x = \frac{49}{20} + \frac{3}{20} \\ \\ </strong><strong>→</strong><strong> x = \frac{49 + 3}{20} \\ \\ </strong><strong>→</strong><strong> x = \frac{52}{20} = \frac{13}{5}$

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Answer 2

Answer:

(1)31/48 (2)13/5

Step-by-step explanation:

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