Question

1. What should be subtracted from 3x + 2y – 3z + 2 to get 2x – 3y + 7?
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Answer 1

$\huge\red{AnsWeR}$

LET THE NO. BE R

$R-(3x+2y-3z+2)=>2x-3y + 7$

$R=>(2x-3y + 7)+(3x+2y-3z+2)$

$R=>2x-3y + 7+3x+2y-3z+2$

$R=>2x+3x-3y+2y+7+2-3z$

$R=>5x-y+9-3z$

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Answer 2

Answer:

(3x+2y-3z+2) - (x+5y-3z-5) = (2x-3y+7)