1. What sum will become 31331 after 3 years at 10% p.a. compound interest?
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Step-by-step explanation:
Given :-
A sum will become 31331 after 3 years at 10% p.a. compound interest
To find:-
Find the sum ?
Solution :-
Let the sum be Rs. X
Amount = Rs. 31331
Time = 3 years
Number of times the compound interest is calculated for 3 years = 3
we know that
Amount = P[1+(R/100)]^n
On Substituting these values in the above formula then
=> 31331 = X[1+(10/100)]³
=> 31331 = X[1+(1/10)]³
=> 31331 = X[(10+1)/10]³
=> 31331 = X(11/10)³
=> 31331 = X(11×11×11)/10×10×10)
=> 31331 = X(1331/1000)
=> 31331 = 1331X/1000
=> 1331X = 31331 × 1000
=> 1331X = 31331000
=> X = 31331000/1331
=> X = 23,539.44
The sum = Rs. 23,539.44
Answer:-
The sum for the given problem is Rs. 23,539.44
Used formulae:-
- Amount = P[1+(R/100)]^n
- P = Principle
- R = Rate of Interest
- n = Number of times the compound interest is calculated per annum
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Answer:
hey your answer is attached above
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