1.What volume (in L) of 0.500 M sodium sulfate will react with 275 mL of 0.250 M barium chloride to completely precipitate all Ba2+ in the solution?
2.What volume of 0.250 M lithium hydroxide will completely react with 0.500 L of 0.250 M of sulfuric acid solution?
3.A 50mg sample of limestone was cautiously dissolved in 1:1 HCL solution on a hot plate. After the sample was completely dissolved, it was allowed to cool to room temperature. The solution was then treated with 20% triethanolamine, and its pH was buffere to 12 using 20% KOH solution. Calcein was added as an indicator and the solution was titrated with 0.0504 M EDTA solution to a salmon pink endpoint. The burette reading reached 8.90 mL. calculate the percentage of the CaO content of the limestone sample
Answers
Answer:
1 0.138 L Na2SO4 solution
2. 1L LiOH solution ( basically 2 mol po yung LiOH di ko po kasi napalitan and the last equation po is supposed to be 0.250 mol LiOH solution instead of 0.5 mol)
Explanation:
Answer:
1) 0.1375 ~ o.138 L of 0.500 M sodium sulfate will react with 275 mL of 0.250 M barium chloride to completely precipitate all Ba2+ in the solution.
2) 0.25 L of 0.250 M lithium hydroxide will completely react with 0.500 L of 0.250 M of sulfuric acid solution.
3) The percentage of the CaO content of the limestone sample is 20%
Explanation
To find the volume of Sodium Sulphate
- Chemical equation
Na2SO4 + BaCl2⇒ BaSO4 + NaCl
- Given
- 275 ml of BaCl2
- 0.250 M BaCl2
- 0.500 M Na2SO4
- Calculations
275 ml of BaCl = 275/ 1000 = 0.275 L
Volume of BaCl2 used= 0.275 x 0.250
= 0.06875 L
Thus, volume of Na2SO4 = 0.06875/0.5
= 0.1375~ 0.138L
To find the volume of Sodium Sulphate
- Chemical equation
LiOH + H2SO4 ⇒ Li2SO4 + 2H20
- Given
- 0.250 M LiOH
- 0.500 L H2SO4
- 0.250 M H2SO4
- Calculations
Volume of LiOH used= 0.250 x 0.500
= 0.125 L
Thus, volume of Na2SO4 = 0.125/0.25
= 0.5 L