Question

1. What volume of 0.5 N NaOH is
required to neutralize 50 ml 1.5 N HCI
solution?
O 200 ml
O 75 ml
O 150 ml
O 100 ml​

Answer 1

Answer:

No of mili Equivalents = Molarity × n-factor × volume(mili liters)

Or No of mili equivalents is also = normality × volume ( mili liters)

No of equivalents of Base added = 0.5 × 100 = 50

No of equivalents of acid = 3 × 10 + 1 × 20 = 50 ( since two acids are added so we have to calculate total equivalents of both acids )

Since milliequivalents of acid and base are equal hence the solution is neutral.

Explanation:

Answer 2

Answer:

option 200ml is right

Explanation:

volume of a 0.5 N NaOH is required to neutralize 50 ml of 1.5 N HCI solution 200 ml