Question

1. What will be the heat generated in an instrument of resistance 1000 is connected to a
potential of 230V.
a) If the time of flow is 5 minute
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Answer 1

Answer:-

• Resistance=R
• Potential Difference=V=230V
• Time=5min

Firstly let's Find power(P) of the instrument

We know

$\boxed{\sf P=\dfrac{V^2}{R}}$

$\\ \tt\hookrightarrow P=\dfrac{(230)^2}{1000}$

$\\ \tt\hookrightarrow P=\dfrac{52900}{1000}$

$\\ \tt\hookrightarrow P=52.9W$

$\\ \tt\hookrightarrow P=53watts(Approx)$

• Heat=H=?

$\boxed{\sf H=Pt}$

$\\ \tt\hookrightarrow Heat=53\times 5$

$\\ \tt\hookrightarrow Heat=265J$

Note:-

SI unit of Heat is Joules(J)