Question

1. What will be the least number,
which is divided by 3, 4, 6 and 9,
leaves a remainder 2. but when
divided by 11 leaves no remainder.​

Answer 1

To approach such questions

We should firstly find the LCM of given no.

I.e. LCM(3,5,6,8,10) = 120

Now as it leaves two as a remainder so the no. Must be in the form 120x + 2.

Here, we will now find the least value for x

120x +2 = 117x + 3x + 2

117 is divisible by 13 , now we have to find x for which 3x+ 2 is divisible by 13

So , x= 8 as 3*8+2= 26

So the no. Will be ,

120x +2 = 120*8 +2 = 960+2=962

Hope it will help you

Please make me brainest as I answered your question first.