Question

1. What will ha
projection is
that will be the effect on maximum height of a projectile when its angle of
action is changed from 30° to 60°, keeping the same initial velocity of
projection?​

Answer 1

Answer:

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In projectile motion, formula for calculating maximum height is h=(u^2sin^2theta)÷g

by putting the given values of theta we get

for 30°

h1=u^2sin^2 (30°)/g,

h1=u^2/4g

for 60°

h2=u^2sin^2 (60°)/g

h2=3u^2/4g

therefore by comparing both the maximum heights we say that 3(h1)= h2.

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