1. What will happen to the volume of an inflated balloon,originally at 20 C, if you take it outdoors where the temperature is 40 C? Assume that pressure is constant and no gas escapes from the balloon.
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Answers
Answered by
0
Answer:
V
1
T
1
=
V
2
T
2
(
T
in Kelvin)
20
o
C
=
20
+
273
=
293
K
150
o
C
=
150
+
273
=
423
K
0.5
293
=
V
2
423
→
V
2
=
0.5
×
423
293
=
0.72
L
Answered by
0
Explanation:
This is an example of Charles' law, sometimes called the temperature-volume law. It states that the volume of a gas is directly proportional to the Kelvin temperature, while pressure and amount are held constant.
The equation is V1T1=V2T2, where V is volume and T is temperature in Kelvins.
Known
V1=0.5 L
T1=20∘C+273.15=293 K
T2=150∘C+273.15=423 K
Unknown
V2
Solution
Rearrange the equation to isolate V2. Substitute the known values into the equation and solve.
V2=V1T2T1
V2=(0.5L×423K)293K=0.7 L rounded to one significant figure
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