Question

1. When 2x square- ax + 7 and ax² + 7x +12 are divided by
(x-3) and (x+1) repectively the remainder in the same
Find the value of a [use remaindre theorem]​

Answer 1

Answer:

a=10

Step-by-step explanation:

let p(x)=2x^2-ax+7

q(x)=ax^2+7x+12

given that when

p(x) divided by (x-3) the remainder p(3)= q(x) when divided by (x+1) the remainder q(-1)

p(3)=18-a+7=25-a

q(-1)=a-7+12=5+a

25-a=5+a

2a=20

a=10