1.When a boat is partially immersed in water ,it displaces 600 kg of water .How much is the buoyant force acting on the boat in Newton's ?(g=10 ms ^-2 )
2.A floating boat displaces water weighting 6000 N .
1.)What is the buoyant force on the best ?
2.(What is the weight of the boat.?
Please give proper ans....
Answers
Answered by
116
Hey,
Ur answer is here,
1.we know that force of buoyancy = density * volume * acceleration due to gravity
given : mass = 600 kg
therefore, force of buoyancy = mass * acceleration due to gravity [ density = mass/volume ]
so,force of buoyancy = 600 * 10 [ taking g as 10 N ]
= 6000 N
2)1.Buoyant force on boat is equal to the weight of water displaced by it, that is 6000 N.
2.Weight of boat is equal to the force exerted on it that is equal to 6000 N.
Hope it helps you ☺️
Ur answer is here,
1.we know that force of buoyancy = density * volume * acceleration due to gravity
given : mass = 600 kg
therefore, force of buoyancy = mass * acceleration due to gravity [ density = mass/volume ]
so,force of buoyancy = 600 * 10 [ taking g as 10 N ]
= 6000 N
2)1.Buoyant force on boat is equal to the weight of water displaced by it, that is 6000 N.
2.Weight of boat is equal to the force exerted on it that is equal to 6000 N.
Hope it helps you ☺️
TANU81:
Thankyou ✌✌✌
Answered by
29
we know that force of buoyancy = density * volume * acceleration due to gravity
given : mass = 600 kg
therefore, force of buoyancy = mass * acceleration due to gravity [ density = mass/volume ]
so,force of buoyancy = 600 * 10 [ taking g as 10 N ]
= 6000 N
given : mass = 600 kg
therefore, force of buoyancy = mass * acceleration due to gravity [ density = mass/volume ]
so,force of buoyancy = 600 * 10 [ taking g as 10 N ]
= 6000 N
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