Question

1.When
two dice are thrown find the probability of
getting a prime doublet?​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

2dice is thrown

sample space (S) =6×6

n)(S) =36

no. of doublet(A) = (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)

n(A) =6

hence, the probability of getting a prime doublet number, =n(A) /n(S) =6/36=1/6