Question

1. Which is correct 'closest approach distance (min) in a
particle experiment when a particle is directed towards
gold nuclei with potential of 10 megavolt. (Z = 79) :​

Answer 1

Answer:

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qwdvchwiqhvdy8e

xbdwu8wdwcwoewc

guqw9cddwcuweygwrcoq

spider man is 3cm and the following equations are consistent

Answer 2

Answer:

At the distance of closest approach the whole kinetic energy get converted into potential energy.

So KE=(1/4πϵ

0

)2Ze

2

/r

Where r is distance of closest approach.

r=

KE×4πϵ

0

2Ze

2

putting Z=50,(1/4πϵ

0

)=9×10

9

,e=1.6×10

−19

,KE=10×1.6×10

−13

Joule

we get r=14.4×10

−15

m

Option D is correct.

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