Math, asked by jeorji, 30 days ago

1. which of the following conditions is not sufficient to prove that a quadrilateral is a parallelogram
a. two pairs of sides are parallel
b. two pairs of opposite sides are congruent
c. two angles are supplementary
d. two diagonals bisect each other

2. which of the following quadrilaterals has diagonals that do not bisect each other?
a. square
b. rhombus
c.rectangle
d. trapezoid ​

Answers

Answered by grajul33
0

Answer:

1)

If both pairs of opposite sides of a quadrilateral are congruent, then it's a parallelogram (converse of a property). ... The only shape you can make is a parallelogram. If both pairs of opposite angles of a quadrilateral are congruent, then it's a parallelogram (converse of a property).

2)

(5) Trapezium: Diagonals are not bisect each other. (6) Kite: Diagonals intersect each other at right angles. From the above result we conclude that diagonals of Rhombus and Square are perpendicular bisector but not rectangle.

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