Question

1. Which of the following contains maximum number of molecules?

(a) 1g Li (b) 1g Au (c) 1g Cu (d) 1g He
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Answer 1

Answer:

(b) 1g Au.

Explanation:

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Answer 2

Concept:

The number of molecules can be calculated using the molar mass.

As 1 mass of the molecule is the molar mass of that molecule.

The number of molecules, n = m/M

where m is given mass and M is the molecular mass or atomic mass.

Given:

Four compounds have a mass of 1 g.

Find:

The one that contains the maximum number of molecules.

Solution:

Calculating the number of molecules,

(a) 1g Li

The atomic mass of Lithium is 7.

Given, m = 1 g Li

Number of molecules, n = m/M = 1/7

(b) 1g Au

The atomic mass of Gold is 197.

Given, m = 1 g Au

Number of molecules, n = m/M = 1/197

(c) 1g Cu

The atomic mass of Copper is 63.5.

Given, m = 1 g Cu

Number of molecules, n = m/M = 1/63.5

(d) 1g He

The atomic mass of Helium is 4.

Given, m = 1 g He

Number of molecules, n = m/M = 1/4

Among the fractions having the same numerator, the fraction having the higher denominator is the lowest and vice-versa.

Hence, 1 g of Helium contains the maximum number of molecules. So, the correct option is (d) 1 g He.

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