Math, asked by neha67687, 28 days ago

1. Which of the following is not equal to??? [(5/6)^1/5]A-1/6? a) (5/6)^1/5-1/6 b) 1/[(5/6)^1/5]41/6 c) (6/5)41/30 d) (5/6)A-1/30​

Answers

Answered by roshandut
1

Answer:

b) 1/[(5/6)^1/5]41/6

Step-by-step explanation:

hope it will help you

Answered by nishajha965804
3

Answer:

The values of the given series 3+4 = 19, 5+6 = 41, 1+3 = ??? is 7.

To find:

Give the Answer if 3+4 = 19, 5+6 = 41, 1+3 = ?

Solution:

Given: 3+4 = 19, 5+6 = 41, 1+3 = ???

3+ 4 = 19

Now, 3+4=7 \text { and } 3 \times 4=123+4=7 and 3×4=12 . If we add 7 + 12, we get 19.

Hence, addition of two given numbers i.e. on L.H.S. + multiplication of given two numbers i.e. on L.H.S. = required answer on R.H.S.

Likewise, 5 + 6 = 41

5+6=11 \text { and } 5 \times 6=305+6=11 and 5×6=30 . If we add 11 + 30, we get 41.

1+3 = ???

\bold{1+3=4 \text { and } 1 \times 3=3}1+3=4 and 1×3=3 . If we add 4 + 3, we get 7.

Hence, 1 + 3 = 7.

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