Question

1.
Which of the following lists of numbers are Arithmetic Progressions ? Justify
(i) 1, 3, 6, 10, ...​

Answer 1

Answer:

Given sequence is,

3,6,12,24,...…

first term of this A.P is a

1

=3

second term of this A.P is a

2

=6

third term of this A.P is a

3

=12

the condition for an sequence to be an A.P is their must be a common difference (i.e.,d=a

n+1

−a

n

)

putting n=1 in above equation

d=a

2

−a

1

=6−3=3

putting n=2 in above equation

d=a

3

−a

2

=12−6=6

as we can see we get two values of d,

but in an A.P their must be a single value of d which means for this sequence we can't define a common difference.

hence this sequence not form an A.P

Step-by-step explanation:

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