Question

1. Which of the following polynomial has -3 as a zero ?
(a) (x-3)
(b)x^2-9
(C) x^2-3x
(d) x^2+3​

Answer 1

Answer:

$-3 \: \: is \: \: zero \: of \: \: the \: \: polynomial \: \: </p><p>(a) \: \: and \: \: (b)$

Step-by-step explanation:

linear equation means

f(x)=0

it is given that x= -3

therefore ,

when we put the x= -3 in given polynomials it will be give zero ans .

put -3 in each options given below ;

a) (x-3)

put x= -3,

(-3-3)=0

hence it will be right answer.

b) x^2-9

put x= -3

(-3)^2-9

=> 9-9=0

hence it is also correct

c) x^2-3x

put x= -3

(-3)^2-3(-3)

9+9=18

-3 is not zero of this polynomial

d)x^2+3

put x= -3

(-3)^2+3

9+3=12

hence, it will not the zero of polynomial

from all this we get that

-3 is zero of the polynomial

(a) and (b)

hope it will helps you

@Ar+nav❤️