1. Which one is not a polynomial
(a) 4x2 + 2x – 1
(b)
(c) x3 – 1
(d) y2 + 5y + 1
2. The polynomial px2 + qx + rx4 + 5 is of type
(a) linear
(b) quadratic
(c) cubic
(d) Biquadratic
3. Identify the polynomial
(a) x–2 + x–1 + 5
(b)
(c)
(d) 3x2 + 7
4. The zero of the polynomial p(x) = 2x + 5 is
(a) 2
(b) 5
(c)
(d)
5. The number of zeros of x2 + 4x + 2
(a) 1
(b) 2
(c) 3
(d) none of these
6. The polynomial of type ax2 + bx + c, a = 0 is of type
(a) linear
(b) quadratic
(c) cubic
(d) Biquadratic
7. The value of k, if (x – 1) is a factor of 4x3 + 3x2 – 4x + k, is
(a) 1
(b) 2
(c) –3
(d) 3
8. The degree of polynomial x + x^2 +1 is
(a) 0
(b) 2
(c) 1
(d) 3
9. If 3 + 5 – 8 = 0, then the value of (3)3 + (5)3 – (8)3 is
(a) 260
(b) –360
(c) –160
(d) 160
10. If value of 104 × 96 is
(a) 9984
(b) 9469
(c) 10234
(d) 11324
11. The value of 5.63 × 5.63 + 11.26 × 2.37 + 2.37 × 2.37 is
(a) 237
(b) 126
(c) 56
(d) 64
12. The value of
(a) 300
(b) 500
(c) 400
(d) 600
13. If x + y = 3, x2 + y2 = 5 then xy is
(a) 1
(b) 3
(c) 2
(d) 5
14. If x + 2 is a factor of x3 – 2ax2 + 16, then value of a is
(a) 3
(b) 1
(c) 4
(d) 2
15. If one of the factor of x2 + x – 20 is (x + 5). Find the other
(a) x – 4
(b) x + 2
(c) x + 4
(d) x – 5
Answers
1. Which one is not a polynomial
Option (b) is correct.
2. The polynomial px2 + qx + rx4 + 5 is of type
Option (d) Biquadratic is correct.
3. Identify the polynomial
Option (d) 3x2 + 7 is correct.
4. The zero of the polynomial p(x) = 2x + 5 is
2x+5 = 0 x = -5/2
5. The number of zeros of x2 + 4x + 2
Option (b) 2 is correct.
6. The polynomial of type ax2 + bx + c, a = 0 is of type
Option (b) quadratic is correct.
7. The value of k, if (x – 1) is a factor of 4x3 + 3x2 – 4x + k, is
x-1 is a factor, then substitute x=1 in the equation 4x3 + 3x2 – 4x + k
4(1)^3 + 3(1)^2 – 4(1) + k = 0
4 + 3 - 4 + k = 0
k = -3
Option (c) –3 is correct
8. The degree of polynomial x + x^2 +1 is
Option (b) 2 is correct
9. If 3 + 5 – 8 = 0, then the value of (3)3 + (5)3 – (8)3 is
3^3 + 5^3 - 8^3
= 27 + 125 - 512 = -360
Option (b) –360 is correct
10. If value of 104 × 96 is
104 × 96 = (100+4) × (100-4) = 100^2 - 4^2 = 10000 - 16 = 9984
Option (a) 9984 is correct.
11. The value of 5.63 × 5.63 + 11.26 × 2.37 + 2.37 × 2.37 is
5.63 × 5.63 + 11.26 × 2.37 + 2.37 × 2.37
= 5.63 × 5.63 + 5.63 × 2 × 2.37 + 2.37 × 2.37
= a × a + 2ab + b × b
= (a + b)^2
= (5.63 + 2.37)^2
= 8^2 = 64
Option (d) 64 is correct.
12. The value of
(a) 300
(b) 500
(c) 400
(d) 600
13. If x + y = 3, x2 + y2 = 5 then xy is
(x + y)^2 = x^2 + y^2 + 2xy
3^2 = 5 + 2xy
9 = 5 + 2xy
4 = 2xy
xy = 2
Option (c) 2 is correct
14. If x + 2 is a factor of x3 – 2ax2 + 16, then value of a is
x+2 is a factor, then substitute x=-2 in the equation x3 – 2ax2 + 16
(-2)^3 - 2a(-2)^2 + 16 = 0
-8 - 8a + 16 = 0
8 - 8a = 0
8 = 8a
a = 1
Option (b) 1 is correct.
15. If one of the factor of x2 + x – 20 is (x + 5). Find the other
x + 5 is a factor of x2 + x – 20 , divide x2 + x – 20 by x + 5
x+5) x^2+x-20 (x+4
x^2+5x
---------------
0 - 4x-20
4x+20
-----------------------
0
Option (c) x + 4 is correct
Which one is not a polynomial
(a) 4x2 + 2x – 1
(b) 
(c) x3 – 1
(d) y2 + 5y + 1
2. The polynomial px2 + qx + rx4 + 5 is of tyep
(a) linear
(b) quadratic
(c) cubic
(d) Biquadratic
3. Identify the polynomial
(a) x–2 + x–1 + 5
(b) 
(c) 
(d) 3x2 + 7
4. The zero of the polynomial p(x) = 2x + 5 is
(a) 2
(b) 5
(c) 
(d) 
5. The number of zeros of x2 + 4x + 2
(a) 1
(b) 2
(c) 3
(d) none of these
6. The polynomial of type ax2 + bx + c, a = 0 is of type
(a) linear
(b) quadratic
(c) cubic
(d) Biquadratic
7. The value of k, if (x – 1) is a factor of 4x3 + 3x2 – 4x + k, is
(a) 1
(b) 2
(c) –3
(d) 3
8. The degree of polynomial  is
(a) 0
(b) 2
(c) 1
(d) 3
9. If 3 + 5 – 8 = 0, then the value of (3)3 + (5)3 – (8)3 is
(a) 260
(b) –360
(c) –160
(d) 160
10. If value of 104 × 96 is
(a) 9984
(b) 9469
(c) 10234
(d) 11324
11. The value of 5.63 × 5.63 + 11.26 × 2.37 + 2.37 × 2.37 is
(a) 237
(b) 126
(c) 56
(d) 64
12. The value of 
(a) 300
(b) 500
(c) 400
(d) 600
13. If x + y = 3, x2 + y2 = 5 then xy is
(a) 1
(b) 3
(c) 2
(d) 5
14. If x + 2 is a factor of x3 – 2ax2 + 16, then value of a is
(a) 3
(b) 1
(c) 4
(d) 2
15. If one of the factor of x2 + x – 20 is (x + 5). Find the other
(a) x – 4
(b) x + 2
(c) x + 4
(d) x – 5
1. (b)2. (d)3. (d)4. (d)5. (b)6. (a)7. (c)8. (c)9. (b)10. (a)11. (d)12. (b)13. (c)14. (b)15. (a)