Math, asked by pav843, 1 year ago

1÷whole root 2011+( root of 2011^2-1)= root m -root n then m+n is equal to what?

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Answered by littyissacpe8b60
14

√m  - n  =                  1          

                 √2011 + √2011² - 1            

x = 2011  


         1             =         (√x - √x² - 1    )               =      (√x - √x² - 1)          

 √x + √x² - 1        (√x -+ √x² - 1) (√x - √x² - 1)             √x² - (x² - 1)                   


  √m - √n  =  √x - √x² - 1  

(√m - √n)² = (√x - √x² - 1)²

m + n - 2√mn = x - √x² - 1


m + n - 2√mn = 2011 - √2011² - 1² = 2011 - √(2011+1)(2011-1)

                       = 2011 - √2010+2012 = 2011 - √1005 x 2 x 2 x 1006

                       = 2011 - 2√1005x1006

∴ m + n = 2011                                          


pav843: want value of m+n
littyissacpe8b60: Sorry I had to do it again. I thought it was to simplify. I hope this is the answer
Answered by snehalmuduli
2

Answer:

the above answer done is right

Step-by-step explanation:

it is of prmo 2012

pls mark me as brainliest

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