1÷whole root 2011+( root of 2011^2-1)= root m -root n then m+n is equal to what?
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√m - n = 1
√2011 + √2011² - 1
x = 2011
1 = (√x - √x² - 1 ) = (√x - √x² - 1)
√x + √x² - 1 (√x -+ √x² - 1) (√x - √x² - 1) √x² - (x² - 1)
√m - √n = √x - √x² - 1
(√m - √n)² = (√x - √x² - 1)²
m + n - 2√mn = x - √x² - 1
m + n - 2√mn = 2011 - √2011² - 1² = 2011 - √(2011+1)(2011-1)
= 2011 - √2010+2012 = 2011 - √1005 x 2 x 2 x 1006
= 2011 - 2√1005x1006
∴ m + n = 2011
pav843:
want value of m+n
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2
Answer:
the above answer done is right
Step-by-step explanation:
it is of prmo 2012
pls mark me as brainliest
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