Question

1. Why does a democratic cou
$5x + 10 = 2x + 8$
solve the following equation by LHS and RHS
​

Answer 1

(a) 5m=60

Putting the given values in L.H.S.,

5 x 10 = 50, 5 x 5 = 25

∵ L.H.S. ≠ R.H.S. ∵ L.H.S.≠ R.H.S.

∴m=10 is not the solution. ∴m=5 is not the solution.

5 x 12 = 60, 5 x 15 = 75

∵ L.H.S. = R.H.S. ∵ L.H.S. ≠ R.H.S.

∴m=12 is a solution. ∴m=15 is not the solution.

(b) n+12=20

Putting the given values in L.H.S.,

12 + 12 = 24, 8 + 12 = 20

∵ L.H.S. ≠ R.H.S. ∵ L.H.S. = R.H.S.

∴n=12 is not the solution. ∴n=8 is a solution.

20 + 12 = 32, 0 + 12 = 12

∵ L.H.S. ≠ R.H.S. ∵ L.H.S. ≠ R.H.S.

∴n=20 is not the solution. ∴n=0 is not the solution.

(c) p–5=5

Putting the given values in L.H.S.,

0 – 5 = –5, 10 – 5 = 5

∵ L.H.S. ≠ R.H.S. ∵ L.H.S. = R.H.S.

∴p=0 is not the solution. ∴p=10 is a solution.

5 – 5 = 0, –5 – 5 = –10

∵ L.H.S. ≠ R.H.S. ∵ L.H.S. ≠ R.H.S.

∴p=5 is not the solution. ∴p=–5 is not the solution.

Answer 2

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