1. Why the size of
(a) Neon greater than fluorine.
(b) Sodium greater than magnesium.
Answers
Answered by
0
Answer:
neon greater than fluorine
Answered by
1
Answer:
- (a)We know that the atomic radius decreases when we go from left to right along a single phase. Similarly, it increases from top to bottom. But there are many exceptions. The position of the neon after fluorine in the second stage is that according to the general rule the radius of the neon should be less. But because neon is an inert element, the repulsive force of electrons in its various sub-cells is created in fluorine. That is why the radius of neon is greater than that of fluorine.
- (b)On the other hand, according to the general rules, the amount of sodium will be higher than that of magnesium because sodium is ahead of magnesium, so its size is larger.
Similar questions