Question

1. William bought some cashews and walnuts. Spending the same amount of money as William, his twin Jillian bought twice as many cashews and 10 less walnuts. If the cost of one walnut is 2 more than the cost of a cashew, then what is the minimum possible number of cashews bought by the twins together?

Answer 1

Solution :-

Let us assume that,

• William bought = C cashews and W walnuts .

1. Cost of 1 cashew = x .

so,

→ Cost of william (cashews + walnuts) = cost of Jilian 2*cashews + (walnuts - 10)

→ xC + (x + 2)W = 2xC + (x + 2)(W - 10)

→ xC + xW + 2W = 2xC + xW - 10x + 2W - 20

→ xC = 2xC - 10x - 20

→ 2xC - xC = 20 - 10x

→ xC = 20 - 10x

→ C = (20 - 10x)/x

now,

• if x = 1 => C = 10
• if x = 2 => C = 0
• if x = 3 => C = Negative integer .
• x more than 2 = Negative integer .

Conclusion :-

• Only or minimum value of cashew is 10 .
• since value of x cant be a negative integer or zero.

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