Question

1
Write a quadratic polynomial, sum of whose zeroes is 2 and product is -8.​

Answer 1

Answer:

(x2-2x-8)

Explanation:

~sum of zeros = 2

~product of zeros = -8

formula to find the quadratic polynomial

k(x2 -sx+p)

k{x2 -2x +(-8)}

k (x2 -2x -8)

let k be 1

==== answer : (x2-2x-8)

thank u

Answer 2

Answer:

x^2-2x+8

Explanation:

let alpha , beta be the 2 roots

we know that

$\alpha + \beta = - b \div a \\ \\ \alpha \beta = c + \div a$

given:

$\alpha + \beta = 2 \\ \alpha \beta = 8$

so after applying the formula we get

a=1,b= -2 , c=8

therefore the equation will be

$ax {}^{2} + bx + c$

after applying the values we get

x^2-2x+8