Question

1 Write an A.P whose first term is 20 and common difference is 8​

Answer 1

Answer:

20,28,36,44,52,60 ...

Step-by-step explanation:

a =20

d =8 so

a2 =a+d

a3 =a2+d

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Answer 2

Given

Write an A.P whose first term is 20 and common difference is 8

Solution

• Common difference (d) = 8

• First term (a) = 20

As we know

$\Large\sf a_n=a+(n-1)d$

So,

$\sf a_1=20$

_________________________

$\sf a_2=20+(2-1)8$

$\sf a_2=20+8$

$\sf a_2 = 28$

_________________________

$\sf a_3 = 20+(3 - 1)8$

$\sf a_3=20+16$

$\sf a_3=36$

_________________________

$\sf a_4 = 20+(4-1)8$

$\sf a_4=20 + 24$

$\sf a_4=44$

_________________________

$\sf a_5=20+(5-1)8$

$\sf a_5=20+32$

$\sf a_5=52$

Hence, 20, 28, 36, 44, 52 ... is in APs

Note

Sum of n term

★ $\sf S_n=\dfrac{n}{2}(2a+(n-1)d)$

★ $\sf S_n=\dfrac{n}{2}(a+l)$

Where , l = last term